Fractions And Decimals(7th Grade > Mathematics ) Questions and answers for exam Preparation

7th Grade > Mathematics

FRACTIONS AND DECIMALS MCQs

Fractions, Decimals

Total Questions : 227 | Page 7 of 23 pages

\frac{5}{7} = \frac{?}{49}

Discuss Question

Answer: Option D. -> 35
:
D
Equivalent fractions are fractions which have the same value and are obtained by dividing or multiplying both the numerator and the denominator of a fraction by the same number.
Now,

49 \div 7 = 7

Therefore,

\frac{5}{7} = \frac{5 \times 7}{7 \times 7} = \frac{35}{49}

Hence, the missing number is 35.

Question 62.

\frac{1}{8}

as a decimal = ______

125
12.5
1.25
0.125

Discuss Question

Answer: Option D. -> 0.125
:
D
8's friend is 125 as

8 \times 125 = 1000

\frac{1}{8} \times \frac{125}{125} = \frac{125}{1000} = 0.125

Question 63.

3 \times \frac{4}{6} + 4 \times \frac{5}{12} - 5 \times \frac{7}{10}

Discuss Question

Answer: Option C. -> 16
:
C

3 \times \frac{4}{6} + 4 \times \frac{5}{12} - 5 \times \frac{7}{10} \frac{3 \times 4}{6} + \frac{4 \times 5}{12} - \frac{5 \times 7}{10} ∴ \frac{4}{2} + \frac{5}{3} - \frac{7}{2} ∴ LCM of 2 \times 3 = 6 ∴ \frac{4 \times 3}{2 \times 3} + \frac{5 \times 2}{3 \times 2} - \frac{7 \times 3}{2 \times 3} 12 + 10 - 21 \frac{22 - 21}{6} = \frac{1}{6}

Question 64. If one pencil costs ₹ 5.75, then the cost of 100 such pencils is _____.

₹ 0.575
₹ 57.50
₹ 575
₹ 5750

Discuss Question

Answer: Option C. -> ₹ 575
:
C
Given: Cost of 1 pencil = ₹ 5.75

∴

Cost of 100 pencils

= ₹ (5.75 \times 100)

\Rightarrow

Cost of 100 pencils = ₹575

Question 65. Find the value.

500 + 4 + \frac{4}{100} =___

54.4
54.04
504.4
504.04

Discuss Question

Answer: Option D. -> 504.04
:
D
We have to do the addition:

= 500 + 4 + \frac{4}{100}

= 500 + 4 + 0.04

500.00 4.00 + 0.04 - -------- - 504.04 - -------- -

Question 66. Six cases of paper cost ₹ 156.49. How much does one cost?

₹ .26.19
₹ 25.45
₹ 26.08
₹ 25.18

Discuss Question

Answer: Option C. -> ₹ 26.08
:
C
cost of six cases = ₹156.49

∴ Cost of one case = \frac{156.49}{6}

\frac{156.49}{6} = 26.08166...

Approximately equal to ₹26.08 (Rounding off).

Question 67. A shopkeeper wants to distribute 20.7 kgs of sugar into 9 equal jars. How much sugar would go into each jar?

2.7 kg
2.1 kg
2.3 kg
3.1 kg

Discuss Question

Answer: Option C. -> 2.3 kg
:
C
To find the amount of sugar that goes into each jar, we need to divide 20.7 kg by 9.

A Shopkeeper Wants To Distribute 20.7 Kgs Of Sugar Into 9 Eq...

∴ \frac{20.7}{9} kg = 2.3 kg

∴

Each jar will have 2.3 kg of sugar.

Question 68.

1.1 - 0.03 =

____

1.7
1.77
1.07
1.70

Discuss Question

Answer: Option C. -> 1.07
:
C
Since 0.03 has two decimal places, we use the equivalent decimal of 1.1 with two decimal places.
i.e.,

1.1 - 0.03 = 1.10 - 0.0.3

1 . / 1^{0} / 0^{10} - 0.03 - --------- - 1.07 - -------- -

Question 69. Solve

\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}

Discuss Question

Answer: Option B. -> 536
:
B

\frac{1}{3} - (\frac{5}{6} \times \frac{9}{18}) + \frac{2}{9}

= \frac{1}{3} - (\frac{15}{36}) + \frac{2}{9}

= \frac{1}{3} - \frac{15}{36} + \frac{2}{9}

Taking L.C.M of denominators,

\frac{12 - 15 + 8}{36} = \frac{5}{36}

Question 70.

\frac{2 \frac{1}{2} + 2 \frac{1}{3} + 2 \frac{1}{4}}{\frac{1}{10} \times \frac{2}{5} \times \frac{125}{6}} is equals to:

Discuss Question

Answer: Option D. -> 8.5
:
D

\frac{\frac{5}{2} + \frac{7}{3} + \frac{9}{4}}{\frac{1}{10} \times \frac{2}{5} \times \frac{125}{6}}

= \frac{\frac{85}{12}}{\frac{5}{6}}

= \frac{85}{12} \times \frac{6}{5}

= \frac{17}{2} = 8.5

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