$\text{Cost of rice in one bag = 25}\times 20.04$
                                  $=₹501$
$\text{Cost of dal in one bag = 20}\times 15.28$
                                 $=₹305.6$
$\text{Total cost of one bag = 501 + 305.6}$
                                                     $=₹806.6$
$\text{Cost of 5 such bags = 5}\times 806.6$
                                      $=₹4033$

$\frac{1}{2}=0.5$

$\frac{5}{2}=2.5$

$\frac{4}{9}=0.4444$

$\frac{5}{20}=0.25$

$\frac{3}{10}=0.3$

$\frac{7}{100}=0.07$

$\frac{100}{2}=50$

$\frac{100000}{10000000}=0.01$

$\frac{12}{48}=0.25$

$\frac{9}{99}=0.09090909$

$\frac{5}{25}=0.20$

∴ $\text{Sum = 54.615}$

When rounded up to two decimal place,

Then $\text{Sum = 54.62}$

Let's take an example and visualize.

$2.48\times 100=248.0$ [Decimal point shifted two places to the right]

$2480÷100=\frac{2480}{100}=24.80$ [Decimal point shifted two places to the left]

$\frac{0.01}{0.001}=0.01\times \frac{1}{0.001}=0.01\times \frac{1000}{1}$
         
         $=10$
$\frac{0.001}{0.01}=0.001\times \frac{1}{0.01}=0.001\times \frac{100}{1}$
         $=$ $0.1$

$⟹$ $\frac{0.01}{0.001}+\frac{0.001}{0.01}$ $=10+0.1=10.1$

Now, the $5^{th}$ decimal place is greater than $5$. So, we add $1$ to the previous digit, which gives $0.3182$

Hence, the required answer is $0.3182$.

Total weight of fruits = 4 kg
Total number of children among whom the fruits are to be shared equally = 5
Thus, the total quantity of fruits each child would get = $\frac{4}{5}\text{kg}$

= $\frac{4}{5}$ $\times 1000\text{grams}$
=$\frac{4000}{5}g$

= 800 g