To write 46 hundredths as a decimal, we use a place value chart.

The answer is 0.46.

Conversion Formula: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Given that
Distance covered by car A in 4 liters of petrol is 5.5 km.
Now 1 km=1000 m.
5.5 km=5500 m

Distance covered by car A in 1 litre of petrol = (5500/4) = 1375 metres

Distance covered by car B in 1 liter of petrol = 1800 meters

So car B travels more compared to car A

Difference = 1800-1375 = 425 metres 
Car B travels  425 meters more than car A

Time taken by Karan to solve a question= 15 seconds
As per the question,

Time taken by Karan's friend to solve the question
= (1/4) of the time taken by Karan to solve the question
 =(15)(1/4) = 3.75 seconds
Hence, Karan's friend will take 3.75 seconds to solve the question.

Formula: 1 Mark
Result: 1 Mark
 We know that area of the rectangle = 50$m^2$

 Given that the length of the rectangle
= $\frac{4}{7}$metres

Now, Length $\times$ breadth= Area of the rectangle
Let the breadth be 'b' meters

$\frac{4}{7}$$\times$b = 50

b = $\frac{175}{2}$ metres
Hence, the breadth of the rectangle is $\frac{175}{2}$ metres.

Concept: 1 Mark
Application: 1 Mark
Given that
Total number of apples = 35

The number of apples each student gets = (35/7) = 5 apples

Total number of bananas = 28              

The number of bananas each student gets =(28/7) = 4 bananas                                                                           

Total number of fruits a student gets = 5 apples + 4 bananas = 9
Hence, each student will get 5 apples and 4 bananas. 

Steps: 1 Mark
Answer: 1 Mark
Let the total work be  W

The work completed by Ramesh = $\frac{1}{10}\times W$

The work completed by Ramesh's friend = $\frac{1}{10}\times \frac{1}{10000}W$

= $\frac{1}{100000}\times W$
Ramesh's friend completes $\frac{1}{100000}$^th  of the work in the given time,

Steps: [1 Marks]
Each answer: [1 Mark]
Time taken by the man in his first attempt = 1 hour

 Time taken by the man in his second attempt = $\frac{1}{4}\times 1$

  =  $\frac{1}{4}$ hour

  Time taken by the man in his third attempt = $\frac{1}{4}\times \frac{4}{5}$

  = $\frac{1}{5}$
Hence he took  $\frac{1}{5}$ hours to complete the work on his third attempt.
The difference in the time taken by him in his first attempt and third attempt
$=1-\frac{1}{5}=\frac{4}{5}hours$

Steps: [2 Marks]
Result: [1 Mark]
Total runs scored by the team that lost = 310 - 10 = 300
Now, total no. of overs played by them = 50
i.e. in 30 overs, this team scored $=\frac{300}{2}$
=150 runs
The balance 300 - 150 = 150 runs were scored by this team in balance 20 overs.
By the given condition
In the next 5 overs $\frac{1}{2}$ of 150 runs
= 75 runs were scored.
$\Rightarrow$ 150 runs - 75 runs = 75 runs are still in balance.
Again in the next 8 overs.
$\frac{1}{5}$ of 75 = 15 runs were scored.
Now No. of overs left = 20 - (5 + 8)
=20 - 13
=7 overs
In seven overs, runs scored will be 75 - 15 = 60 runs

Visualizing the question : 1 Mark
Steps : 1 Mark
Result : 1 Mark

Area of the given circle = 400 $m^2$

Area of each sector= $\frac{400}{4}=100m^2$

Area of the shaded portion = $\frac{100}{2}$ 
= $50m^2$