7th Grade > Mathematics
FRACTIONS AND DECIMALS MCQs
Fractions, Decimals
Total Questions : 227
| Page 17 of 23 pages
Answer: Option B. -> 5.25 hours
:
B
60 minutes = 1 hour
1 minute = 160 hour
Therefore 15 minutes =160×15= 0.25 hours
So, 5 hours and 15 minutes is
5 + 0.25 = 5.25 hours
:
B
60 minutes = 1 hour
1 minute = 160 hour
Therefore 15 minutes =160×15= 0.25 hours
So, 5 hours and 15 minutes is
5 + 0.25 = 5.25 hours
Answer: Option C. -> Forty five point seven nine
:
C
The numbers left to the decimal are written in words like normal numbers but the numbers right to the decimal point are written as a digit at once.
So the given number in words will be, forty-five point seven nine
:
C
The numbers left to the decimal are written in words like normal numbers but the numbers right to the decimal point are written as a digit at once.
So the given number in words will be, forty-five point seven nine
Answer: Option C. -> 1.50
:
C
Since there are 4 divisions between 1 and 2, each division corresponds to the fraction 14.
But, 14=0.25.
So, the point A represents the decimal =1+0.25+0.25=1.50
:
C
Since there are 4 divisions between 1 and 2, each division corresponds to the fraction 14.
But, 14=0.25.
So, the point A represents the decimal =1+0.25+0.25=1.50
Answer: Option D. -> 0.09
:
D
The percentagehas increased because 90.98 is greater than 90.89. The increase is (90.98 - 90.89) = 0.09
:
D
The percentagehas increased because 90.98 is greater than 90.89. The increase is (90.98 - 90.89) = 0.09
Answer: Option C. -> 5.20
:
C
110=0.1
So, 5+0.1+0.1=5.2=5.20
:
C
110=0.1
So, 5+0.1+0.1=5.2=5.20
Answer: Option C. -> ₹ 3.75
:
C
Amount paid = ₹30
Total bill = ₹5.50 + ₹20.75 = ₹26.25
Amount returned by shopkeeper = ₹30 - ₹26.25 = ₹3.75
:
C
Amount paid = ₹30
Total bill = ₹5.50 + ₹20.75 = ₹26.25
Amount returned by shopkeeper = ₹30 - ₹26.25 = ₹3.75
Answer: Option B. ->
536
:
B
:
B
13−(56×918)+29
=13−(1536)+29
=13−1536+29
Taking L.C.M of denominators, 12−15+836=536
Answer: Option C. ->
1890512
:
C and D
:
C and D
12×(1+14)×(1+24)×(1+34)×(1+54)
= 12 ×54×64×74×94=945256
Answer: Option B. ->
161
:
B
:
B
(124 -12 +3616 -116 +28)
=64 −12 +5416 −116 +28
Taking LCM of denominators and solving,
24 −8 +54 −1 +416=7316
Now, If we multiply 7316 by 161, it becomes 73, which is an integer
Hence, 161 is the required fraction.