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7th Grade > Mathematics

EXPONENTS AND POWERS MCQs

Total Questions : 102 | Page 5 of 11 pages
Question 41. A man has many chocolates and he takes 37 chocolates and distributes it to 34 students. How many chocolates do each student get if each student should get an equal number of chocolates?  [2 MARKS]
 Discuss Question

:
Concept: 1 Mark
Answer:1 Mark
Given that,
A man has many chocolates and he takes 37chocolates.
He has to distribute them equally between34students.

The number of chocolates a student gets is:
=3734
=374 [aman=amn]
=33
=27
So, each student will get 27 chocolates.
Question 42. Find the value of 'n' if (am)2n=a2m. Find the numerical value of  a2m if a=2 and m=4.  [4 MARKS]
 Discuss Question

:
Formula: 1 Mark
Value of n: 1 Mark
Numerical value: 1 Mark
Steps: 1 Mark
Given that,
(am)2n=a2m
a2mn=a2m [(am)n=amn]

Since bases are same, their exponents also should be equal.
2mn=2m
n=2m2m
n=1
As per question,
a=2 and m=4

On substituting the values, we get:
a2m=22×4
=28
=2×2×2×2×2×2×2×2
=256
Hence, the required value is 256.
Question 43. Third power of 14× fourth power of 4 equals to ______.
  1.     42
  2.     43
  3.     4
  4.     40
 Discuss Question
Answer: Option C. ->  4
:
C
Third power of 14=(14)3
Fourth power of 4 is equal to 44.
(14)3×44
= 14×14×14×4×4×4×4
= 4×4×4×44×4×4
= 4443
= 4
Question 44. Express 5126000 in standard form. 
  1.    0.5126×107
  2.    5.126×106
  3.    51.26×105
  4.    5126×103
 Discuss Question
Answer: Option B. -> 5.126×106
:
B
In standard form, any number is expressed in powers of 10. The decimal number must be in between 1 and 10.
5.126×1000000=5.126×106
Question 45.  23×33
___
 Discuss Question

:
23×33=(2×3)3=63=216
Question 46. The value of 43×23 is 
 
 Discuss Question

:
Notice that here the two terms43 and 23have different bases, but the same exponents.
43×23=(4×4×4)×(2×2×2)
=(4×2)×(4×2)×(4×2)=83=512
Question 47. If a = 2 and b = 3, find the value of (ab)a.
  1.    16
  2.    32
  3.    64
  4.    128
 Discuss Question
Answer: Option C. -> 64
:
C
On substitutinga = 2 and b = 3, we get
(23)2=23×2[(xm)n=x(m×n)]
=26
=64
Question 48. Express 256×243 in exponential form.
  1.    28×35
  2.    27×34
  3.    26×33
  4.    22×32
 Discuss Question
Answer: Option A. -> 28×35
:
A
We can write:
256=(2×2×2×2×2×2×2×2)=28
243=(3×3×3×3×3)=35
256×243=28×35
Question 49. 3×1000+2×10+410+31000 is the expanded form of the number ____.
  1.    3200.430
  2.    3002.403
  3.    32.430
  4.    3020.403
 Discuss Question
Answer: Option D. -> 3020.403
:
D
3×1000+2×10+410+31000
=3000+20+0.4+0.003
=3020.403
Question 50.


Express 343 as a power of 7.


  1.     72
  2.     73
  3.     74
  4.     70
 Discuss Question
Answer: Option B. -> 73
:
B

343 can be written as
343=7×7×7
so, 343=73


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