Exponents And Powers(7th Grade > Mathematics ) Questions and answers for exam Preparation

EXPONENTS AND POWERS MCQs

Total Questions : 102 | Page 11 of 11 pages

Question 101.

Find the value of $(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{6}$ .

Discuss Question

Answer: Option C. ->

\frac{- 2}{5}

:
C

$\frac{a^{b}}{a^{c}} = a^{b - c}$ [a is a non-zero integer]

Using this law, we get,
$(\frac{- 2}{5})^{7} \div (\frac{- 2}{5})^{6}$

${(\frac{- 2}{5})}^{7 - 6} = {(\frac{- 2}{5})}^{1} = \frac{- 2}{5}$

Question 102.

The value of $(3^{0} - 2^{0}) \times 5^{2}$ is:

Discuss Question

Answer: Option C. -> 0
:
C

$∵$ For any number a $\neq$ 0, a $^{0}$ = 1.

$∴ 3^{0} = 2^{0} = 1$
$\Rightarrow (3^{0} - 2^{0}) \times 5^{2} = (1 - 1) \times 25 = 0$

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