Question
Find the value of 'n' if (am)2n=a2m. Find the numerical value of a2m if a=2 and m=4. [4 MARKS]
Answer:
:
Formula: 1 Mark
Value of n: 1 Mark
Numerical value: 1 Mark
Steps: 1 Mark
Given that,
(am)2n=a2m
a2mn=a2m [∵(am)n=amn]
Since bases are same, their exponents also should be equal.
⇒2mn=2m
⇒n=2m2m
⇒n=1
As per question,
a=2 and m=4
On substituting the values, we get:
a2m=22×4
=28
=2×2×2×2×2×2×2×2
=256
Hence, the required value is 256.
Was this answer helpful ?
:
Formula: 1 Mark
Value of n: 1 Mark
Numerical value: 1 Mark
Steps: 1 Mark
Given that,
(am)2n=a2m
a2mn=a2m [∵(am)n=amn]
Since bases are same, their exponents also should be equal.
⇒2mn=2m
⇒n=2m2m
⇒n=1
As per question,
a=2 and m=4
On substituting the values, we get:
a2m=22×4
=28
=2×2×2×2×2×2×2×2
=256
Hence, the required value is 256.
Was this answer helpful ?
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