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Quantitative Aptitude

AGES MCQs

Problems On Ages

Total Questions : 432 | Page 8 of 44 pages
Question 71.

One year ago the ratio between Samir and Ashok’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years?

  1.    15
  2.    16
  3.    17
  4.    18
  5.    None of these
 Discuss Question
Answer: Option B. -> 16

 -  Let one year ago
Samir’s age be 4X years
And, Ashok’s age be 3X years
Present age of Samir = (4X + 1) years
Present age of Ashok = (3X + 1) years
One year hence
Samir’s age = (4X + 2) years
Ashok’s age = (3X + 1) years
According to question,
  4X + 2 = 5   16 + 8 = 15X + 10   3X + 2 4  
or,       X = 2
Sum of their present ages = 4X + 1 + 3X + 1
= 7X + 2
= 7 x 2 + 2 = 16 years.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 72.

A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son’s age five years back was:

  1.    14
  2.    19
  3.    38
  4.    40
  5.    None of these
 Discuss Question
Answer: Option A. -> 14
 -  Let son’s present age be X years. Then, (38 – X) = X
2X = 38
X = 19
Son's age 5 years back = (19 - 5) years = 14 years
Question 73.

Ratio of Ashok's age to pradeep's age is 4:3. Ashok willl be 26 years old after 6 years. How old is Pradeep now?

  1.    15
  2.    18
  3.    20
  4.    25
  5.    None of these
 Discuss Question
Answer: Option A. -> 15
 -  Let the present ages of Ashok and Pradeep be 4X and 3X
So that 4X + 6 = 26
X = 5
Present age of Pradeep is 3X = 3 x 5, i.e. 15 years
Question 74.

The ages of Ram and Mukta are in the ratio of 3 : 5. After 9 years, the ratio of their ages will become 3 : 4. The present age of Muka (in years) is:

  1.    15
  2.    20
  3.    25
  4.    30
  5.    None of these
 Discuss Question
Answer: Option A. -> 15

 -  Let Ram's age = 3X and Mukta's age = 5X
  3X + 9 = 3       4 (3X + 9) = 3 (5X + 9) 5X + 9 4
Mukta's age = 15 years.

Let's assume that the present age of Mukta is 5x years.

Then, the present age of Ram will be 3x years.

After 9 years, the age of Mukta will become 5x + 9 years, and the age of Ram will become 3x + 9 years.

The given ratio of their ages after 9 years is 3 : 4. Hence,

(3x + 9) / (5x + 9) = 3/4

Cross-multiplying, we get:

12x + 108 = 15x + 135

Solving for x, we get:

3x = 27

Hence, x = 9.

Therefore, the present age of Mukta is 5x = 5 * 9 = 45 years.

To summarize:

The present age of Mukta is 45 years.

Answer: A - 15.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 75.

The average age of class of 50 students is 24 years. If the average of 10 of them is 22 years, while average of another 10 is 26 years. What is the average of the remaining 30 students?

  1.    22 years
  2.    24 years
  3.    26 years
  4.    30 years
  5.    None of these
 Discuss Question
Answer: Option B. -> 24 years

 -     Difference Total
50 Students
(22 Years) - 2 =>
10 (26 Years) + 2 =>
30(?) -20
+20
Observe that 10 students have an average of 22 years (2 years below 24). While another 10 students
have an average of 26 years (2 years above 24). Thus, the effect by (-2) is nullified by the effect of
(+2).As such, the average of remaining 30 students would remain same as 24 years.

Let the average age of the remaining 30 students be x.

We know that the average age of the entire class of 50 students is 24 years. Therefore, the total age of all the students is:

50 * 24 = 1200 years

We also know that the average age of 10 of the students is 22 years. Therefore, the total age of these 10 students is:

10 * 22 = 220 years

Similarly, the total age of the other 10 students whose average age is 26 years is:

10 * 26 = 260 years

Now, let's use the formula for the average:

Average = (Sum of values) / (Number of values)

We can use this formula to find the total age of the remaining 30 students:

Total age of remaining 30 students = (50 * 24) - 220 - 260

Total age of remaining 30 students = 1200 - 480

Total age of remaining 30 students = 720

Therefore, the average age of the remaining 30 students is:

Average age of remaining 30 students = Total age of remaining 30 students / Number of remaining students

Average age of remaining 30 students = 720 / 30

Average age of remaining 30 students = 24

Hence, the correct answer is option B, which is 24 years.

If you think the solution is wrong then please provide your own solution below in the comments section .

Question 76.

Five years ago Mr. Sohanlal was thrice as old as his son and ten years hence he will be twice as old as his son. Mr. Sohanlal’s present age (in years) is:

  1.    20 years
  2.    30 years
  3.    40 years
  4.    50 years
  5.    None of these
 Discuss Question
Answer: Option D. -> 50 years

 -  Let Mr. Sohanlal’s age (in years) = X and his son’s age =Y
Then, X – 5 = 3(Y – 5) i.e. X – 3Y + 10 = 0
And, X + 10 = 2 (Y + 10) i.e. X – 2Y – 10 = 0
Solving the two equations, we get
X = 50, Y = 20.

Let Mr. Sohanlal's present age be x years and his son's present age be y years.
Then, according to the given information, five years ago,

x - 5 = 3(y - 5)
=> x - 5 = 3y - 15
=> x = 3y - 10

Also, ten years hence,

x + 10 = 2(y + 10)
=> x + 10 = 2y + 20
=> x = 2y + 10

Substituting the value of x from equation (1) in equation (2),

3y - 10 = 2y + 10
=> y = 20

Hence, Mr. Sohanlal's present age = 3 × 20 = 50 years

Therefore, the correct answer is Option D. 50 years.

Question 77.

Ayesh's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?

  1.    3 years
  2.    4 years
  3.    5 years
  4.    6 years
  5.    None of these
 Discuss Question
Answer: Option D. -> 6 years
 -  Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 – 36) years = 6 years.
Question 78.

The sum of ages a father and son is 45 years. Five years ago, the product of their ages was four times the father’s age at that time. The present age of the father is:

  1.    35 years
  2.    36 years
  3.    37 years
  4.    38 years
  5.    None of these
 Discuss Question
Answer: Option B. -> 36 years
 -  Let father’s present age = X years
Then, son’s present age = (45 – X) years
Given: (X – 5)(45 – X – 5) = 4(X – 5)
or,       X2-41X+180 = 0 or, (X-36)(X-5) = 0
X = 36 years.
Question 79.

A person was asked to state his age in years. His reply was, "Take my age three years hence, multiply it by 3 and then subtract three times my age three years ago and you will know how old I am." What was the age of the person?

  1.    18 years
  2.    19 years
  3.    20 years
  4.    22 years
  5.    None of these
 Discuss Question
Answer: Option A. -> 18 years
 -  Let the present age of the person be X years.
Then, 3 (X + 3) - 3 (X - 3) = X         (3X + 9) - (3X - 9) = X
X = 18
Question 80.

The average of class of 30 students is 21 years. When the teacher's age is included, the average increases by 1. What is teacher's age?

  1.    28 years
  2.    32 years
  3.    43 years
  4.    52 years
  5.    None of these
 Discuss Question
Answer: Option D. -> 52 years

 -  Avg x Number = Total
30 nos x 21 years = 630 years                   …..(1)
30 nos x 22 years = 682 years                   …..(2)
Teacher's age = (2) - (1) = 682 - 630 = 52 years.

Average is the sum of all the values divided by the number of values.

Therefore, the average of the 30 students (without the teacher) = 21

Let 'x' be the teacher's age.

Therefore, the average of the 30 students (including the teacher) = 21 + 1 = 22

Formula for Average:
Average = Sum of all values/ Number of values

Therefore,
22 = (30×21 + x)/31

On solving the above equation,
x = 31×22 - 30×21
= 682 - 630
= 52

Hence, the teacher's age is 52 years.

Therefore, the correct option is option D: 52 years.

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