Five years ago Mr. Sohanlal was thrice as old as his son and ten years hence he will be twice as old as his son. Mr. Sohanlal’s present age (in years) is:
- Let Mr. Sohanlal’s age (in years) = X and his son’s age =Y
Then, X – 5 = 3(Y – 5) i.e. X – 3Y + 10 = 0
And, X + 10 = 2 (Y + 10) i.e. X – 2Y – 10 = 0
Solving the two equations, we get
X = 50, Y = 20.
Let Mr. Sohanlal's present age be x years and his son's present age be y years.
Then, according to the given information, five years ago,
x - 5 = 3(y - 5)
=> x - 5 = 3y - 15
=> x = 3y - 10
Also, ten years hence,
x + 10 = 2(y + 10)
=> x + 10 = 2y + 20
=> x = 2y + 10
Substituting the value of x from equation (1) in equation (2),
3y - 10 = 2y + 10
=> y = 20
Hence, Mr. Sohanlal's present age = 3 × 20 = 50 years
Therefore, the correct answer is Option D. 50 years.
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