Question
The sum of ages a father and son is 45 years. Five years ago, the product of their ages was four times the father’s age at that time. The present age of the father is:
Answer: Option B
- Let father’s present age = X years
Then, son’s present age = (45 – X) years
Given: (X – 5)(45 – X – 5) = 4(X – 5)
or, X2-41X+180 = 0 or, (X-36)(X-5) = 0
X = 36 years.
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- Let father’s present age = X years
Then, son’s present age = (45 – X) years
Given: (X – 5)(45 – X – 5) = 4(X – 5)
or, X2-41X+180 = 0 or, (X-36)(X-5) = 0
X = 36 years.
Was this answer helpful ?
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