A works twice as fast as B. If B can complete a work in 12 days independently, t

Question

A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in :

Options:

A . 4 days

B . 6 days

C . 8 days

D . 18 days

Answer: Option A

Ratio of rates of working of A and B = 2 : 1.

So, ratio of times taken = 1 : 2.

B's 1 day's work = \(\frac{1}{12}\)

So, A's 1 day's work = \(\frac{1}{6}\) ; (2 times of B's work)

(A + B)'s 1 day's work = \(\left(\frac{1}{6}+\frac{1}{12}\right)=\frac{3}{12}=\frac{1}{4}.\)

So, A and B together can finish the work in 4 days.

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