Question
#include<stdio.h>#define CUBE(x) (x*x*x)
#define CUBE(x) (x*x*x)
int main()
{
int a, b=3;
a = CUBE(b++);
printf("%d, %d\n", a, b);
return 0;
}
What will be the output of the program?
#include<stdio.h>#define CUBE(x) (x*x*x)
#define CUBE(x) (x*x*x)
int main()
{
int a, b=3;
a = CUBE(b++);
printf("%d, %d\n", a, b);
return 0;
}
Answer: Option C
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The macro function CUBE(x) (x*x*x) calculates the cubic value of given number(Eg: 103.)
Step 1: int a, b=3; The variable a and b are declared as an integer type and varaible b id
initialized to 3.
Step 2: a = CUBE(b++); becomes
=> a = b++ * b++ * b++;
=> a = 3 * 3 * 3; Here we are using post-increement operator, so the 3 is not incremented in
this statement.
=> a = 27; Here, 27 is store in the variable a. By the way, the value of variable b is incremented
by 3. (ie: b=6)
Step 3: printf("%d, %d`setminus`n", a, b); It prints the value of variable a and b.
Hence the output of the program is 27, 6.
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