Question
#include<stdio.h>
#define SQR(x)(x*x)
int main()
{
int a, b=3;
a = SQR(b+2);
printf("%d\n", a);
return 0;
}
What will be the output of the program?
#include<stdio.h>
#define SQR(x)(x*x)
int main()
{
int a, b=3;
a = SQR(b+2);
printf("%d\n", a);
return 0;
}
Answer: Option B
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The macro function SQR(x)(x*x) calculate the square of the given number 'x'. (Eg: 102)
Step 1: int a, b=3; Here the variable a, b are declared as an integer type and the variable b
is initialized to 3.
Step 2: a = SQR(b+2); becomes,
=> a = b+2 * b+2; Here SQR(x) is replaced by macro to x*x .
=> a = 3+2 * 3+2;
=> a = 3 + 6 + 2;
=> a = 11;
Step 3: printf("%d`setminus`n", a); It prints the value of variable 'a'.
Hence the output of the program is 11
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