Question
#include<stdio.h>
#define MAN(x, y) ((x)>(y)) ? (x):(y);
int main()
{
int i=10, j=5, k=0;
k = MAN(++i, j++);
printf("%d, %d, %d\n", i, j, k);
return 0;
}
What will be the output of the program?
#include<stdio.h>
#define MAN(x, y) ((x)>(y)) ? (x):(y);
int main()
{
int i=10, j=5, k=0;
k = MAN(++i, j++);
printf("%d, %d, %d\n", i, j, k);
return 0;
}
Answer: Option A
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The macro MAN(x, y) ((x)>(y)) ? (x):(y); returns the biggest number of given two numbers.
Step 1: int i=10, j=5, k=0; The variable i, j, k are declared as an integer type and initialized to
value 10, 5, 0 respectively.
Step 2: k = MAN(++i, j++); becomes,
=> k = ((++i)>(j++)) ? (++i):(j++);
=> k = ((11)>(5)) ? (12):(6);
=> k = 12
Step 3: printf("%d, %d, %d`setminus`n", i, j, k); It prints the variable i, j, k.
In the above macro step 2 the variable i value is increemented by 2 and variable j value is
increemented by 1.
Hence the output of the program is 12, 6, 12
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