Question
Two plane mirrors are initially inclined at 30° and they are moved apart by 30° each time, till the angle between them becomes 120°. If an object is placed symmetrically between them then find the sum of all the images formed.
Answer: Option B
:
B
Herenumber of images formed during each occassionis noted and added
Number of images formed = n =(360∘θ−1)
Total number of images =Number of images when angle between mirrors is at 30°, 60°, 90°and 120°
n = (360∘30∘−1)+ (360∘60∘−1)+ (360∘90∘−1)+ (360∘120∘−1)
n = 11 + 5 + 3 + 2 = 21
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B
Herenumber of images formed during each occassionis noted and added
Number of images formed = n =(360∘θ−1)
Total number of images =Number of images when angle between mirrors is at 30°, 60°, 90°and 120°
n = (360∘30∘−1)+ (360∘60∘−1)+ (360∘90∘−1)+ (360∘120∘−1)
n = 11 + 5 + 3 + 2 = 21
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