Question
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Answer: Option C
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours
$$\eqalign{
& \therefore \frac{1}{x} + \frac{1}{{ {x + 6} }} = \frac{1}{4} \cr
& \Rightarrow \frac{{x + 6 + x}}{{x\left( {x + 6} \right)}} = \frac{1}{4} \cr
& \Rightarrow {x^2} - 2x - 24 = 0 \cr
& \Rightarrow \left( {x - 6} \right)\left( {x + 4} \right) = 0 \cr
& \Rightarrow x = 6\,{\kern 1pt} {\kern 1pt} \left[ {{\text{neglecting the negative value of }}x} \right] \cr} $$
Was this answer helpful ?
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours
$$\eqalign{
& \therefore \frac{1}{x} + \frac{1}{{ {x + 6} }} = \frac{1}{4} \cr
& \Rightarrow \frac{{x + 6 + x}}{{x\left( {x + 6} \right)}} = \frac{1}{4} \cr
& \Rightarrow {x^2} - 2x - 24 = 0 \cr
& \Rightarrow \left( {x - 6} \right)\left( {x + 4} \right) = 0 \cr
& \Rightarrow x = 6\,{\kern 1pt} {\kern 1pt} \left[ {{\text{neglecting the negative value of }}x} \right] \cr} $$
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution