Question
A pipe can fill a tank with water in 3 hours. Due to leakage in bottom, it takes $$3\frac{1}{2}$$ hours to fill it. In what time the leak will empty the completely filled tank?
Answer: Option B
Let the total capacity of tank is 21 units
A's efficiency is 7 units/hr
A's efficiency after leakage 6 units/hr
leakage efficiency = 7 - 6 = 1 unit/hr
leakage will empty the filled tank
$$\frac{{{\text{Total Capacity}}}}{{{\text{Efficiency }}}} = \frac{{21}}{1}$$
= 21hours
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Let the total capacity of tank is 21 units
A's efficiency is 7 units/hr
A's efficiency after leakage 6 units/hr
leakage efficiency = 7 - 6 = 1 unit/hr
leakage will empty the filled tank
$$\frac{{{\text{Total Capacity}}}}{{{\text{Efficiency }}}} = \frac{{21}}{1}$$
= 21hours
Was this answer helpful ?
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