Question
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one.
Answer: Option B
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Relative speed = \(\left(45+30\right)m/sec\)
= \(\left(75\times\frac{5}{18}\right)m/sec\)
=\(\left(\frac{125}{6}\right)m/sec.\)
We have to find the time taken by the slower train to pass the DRIVER of the faster train and not the complete train.
So, distance covered = Length of the slower train.
Therefore, Distance covered = 500 m.
Therefore. = \(\left(500\times\frac{6}{125}\right) = 24sec.\)
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