Question
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:
Answer: Option D
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Let the speed of the second train be x km/hr.
Relative speed = \(\left(x+50\right)km/hr\)
= \(\left[(x+50)\times\frac{5}{18}\right]m/sec\)
=\(\left[\frac{250+5x}{18}\right]m/sec.\)
Distance covered = (108 + 112) = 220 m.
\(\therefore \frac{220}{\left[\frac{250+5x}{18}\right]}=6\)
250 + 5x = 660
x = 82 km/hr.
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