Question
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?
Answer: Option B
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Speed of the first train = \(\left(\frac{120}{10}\right)m/sec = 12m/sec.\)
Speed of the second train =\(\left(\frac{120}{15}\right)m/sec = 8m/sec\)
Relative speed = (12 + 8) = 20 m/sec.
Therefore Required time = \(\left[\frac{(120+120)}{20}\right]sec = 12sec.\)
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