Question
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option A
- Relative sped = (60 + 90) km/hr
= [150 x 5/18] m/sec = [125 / 3] m/sec.
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = [2000 x 3/125] sec = 48 sec.
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- Relative sped = (60 + 90) km/hr
= [150 x 5/18] m/sec = [125 / 3] m/sec.
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = [2000 x 3/125] sec = 48 sec.
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