Question
Total number of moles for the reaction 2HI ⇋ H2 + I2 if α is degree of
dissociation is
dissociation is
Answer: Option A
:
A
Initially 2HI⇋H2+I2
Moles of HI=2,H2=0,I2=0
At equilibrium,
Moles of HI=2−α,H2=α2,I2=α2
Total moles = 2−α+α2+α2=2
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:
A
Initially 2HI⇋H2+I2
Moles of HI=2,H2=0,I2=0
At equilibrium,
Moles of HI=2−α,H2=α2,I2=α2
Total moles = 2−α+α2+α2=2
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