Question
The dissociation constant of a weak acid is 1.0 × 10−5. The equilibrium
constant for the reaction with strong base is
constant for the reaction with strong base is
Answer: Option C
:
C
HA⇋H++A−;Ka=[H+][A−][HA]….(i)
neutralization of the weak acid with strong base is
HA+OH−⇋A−+H2O ….(ii)
K=[A−][HA][OH−]
dividing (i) by (ii) KaK=[H+][OH−]=Kw=10−14
K=KaKw=10−510−14=109
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:
C
HA⇋H++A−;Ka=[H+][A−][HA]….(i)
neutralization of the weak acid with strong base is
HA+OH−⇋A−+H2O ….(ii)
K=[A−][HA][OH−]
dividing (i) by (ii) KaK=[H+][OH−]=Kw=10−14
K=KaKw=10−510−14=109
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