Question
The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10−5 mol l−1. Its
solubility product number will be
solubility product number will be
Answer: Option A
:
A
AB2⇋A++2B−
At equilibrium, [A+]=1×10−5,[B−]=2×10−5
Ksp=[1×10−5][2×10−5]2=4×10−15
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:
A
AB2⇋A++2B−
At equilibrium, [A+]=1×10−5,[B−]=2×10−5
Ksp=[1×10−5][2×10−5]2=4×10−15
Was this answer helpful ?
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