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Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are  open for  one hour  each  alternately, the tank  will  be full  in :


Options:
A .  6 hrs.
B .  `6 2/3`hrs.
C .  7 hrs.
D .  `7 1/2`hrs.
Answer: Option C

(A + B)'s 1 hour's work =  `(1/12 + 1/15) = 9/60 =  3/20`.

(A + C)'s 1 hour's work = `(1/12 + 1/20) = 8/60 = 2/15`.

part filled in 2 hrs. = `(3/20 + 2/15) = 17/60` .

part filled in  6 hrs. = `(3 xx 17/60) = 17/20`.

Remaining part = `(1 - 17/20) = 3/20`.

Now, it is the turn of A and B  `3/20` part is filled by A and B in 1 hour.

`:.`        Total time taken to fill the tank = (6 +1) hrs. = 7 hrs.



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