Question
Two pipes A and B can fill a tank in 6 hours and 4 hours respectively . If hey are opened on alternate hours and if pipe A is opened first . in how many hours. the tan shall be full ?
Answer: Option C
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A's work in 1 hour = `1/6`,
B's work in 1 hour = `1/4`
(A + B)'s 2 hour's work when opened alternately = `(1/6 + 1/4) = 5/12`
(A + B)'s 4 hour's work when opened alternately = `10/12 = 5/6`.
Remaining part = `(1 - 5/6) = 1/6`
Now, it is A's turn and `1/6` part is filled by A in 1 hour.
`:.` Total time taken to fill the tank = (4 + 1) hrs. = 5 hrs.
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