Question
The time period of the simple harmonic motion represented by the equation d2xdt2+αx=0 is
Answer: Option D
:
D
In a simple harmonic motion d2xdt2=−ω2x where ω is the angular frequency. Comparing it with d2xdt2=−αx we get ω2=αorω=√αor2πT=√αorT=2π√α, Hence the correct choice is (d)
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:
D
In a simple harmonic motion d2xdt2=−ω2x where ω is the angular frequency. Comparing it with d2xdt2=−αx we get ω2=αorω=√αor2πT=√αorT=2π√α, Hence the correct choice is (d)
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