Question
A particle is executing linear simple harmonic motion of amplitude A. What fraction of the total energy is kinetic when the displacement is half the amplitude?
Answer: Option D
:
D
Kinetic energy (KE)=12mω2(A2−x2)
Potential energy (PE)=12mω2x2
Total energy (E)=12mω2A2Whenx=A2
KE = 12mω2(A2−A24)=38mω2A2E=12mω2A2∴KEE=34
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:
D
Kinetic energy (KE)=12mω2(A2−x2)
Potential energy (PE)=12mω2x2
Total energy (E)=12mω2A2Whenx=A2
KE = 12mω2(A2−A24)=38mω2A2E=12mω2A2∴KEE=34
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