Question
The remainder obtained when 100*(9910) is divided by (100*99) + 1 is
Answer: Option D
:
D
Option (d)
Go from unitary method, try for smaller numbers. Consider 10x910 = (10.9)99
(10x9)+1
Consider the remainder when 9991. go by frequency method.
9191∣∣R=9
9191∣∣R=-10
9391∣∣R= -90/91|R=+1
Therefore 9991∣∣R=1
Remainder will be only the first part of the numerator=10x9, in the case we have considered = 90
And in the question = 100x99= 9900
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:
D
Option (d)
Go from unitary method, try for smaller numbers. Consider 10x910 = (10.9)99
(10x9)+1
Consider the remainder when 9991. go by frequency method.
9191∣∣R=9
9191∣∣R=-10
9391∣∣R= -90/91|R=+1
Therefore 9991∣∣R=1
Remainder will be only the first part of the numerator=10x9, in the case we have considered = 90
And in the question = 100x99= 9900
Was this answer helpful ?
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