Question
Four distinct numbers are selected from first 100 natural numbers. How many numbers are there which are divisible by both 3 and 5?
Answer: Option D
:
D
Option(d)
A number divisible by both 3 as well as 5 has to be divisible by 15. In the first 100 natural numbers, there are 6 such numbers-> 15, 30, 45, 60, 75, 90
Favourable number of ways = 6C4
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:
D
Option(d)
A number divisible by both 3 as well as 5 has to be divisible by 15. In the first 100 natural numbers, there are 6 such numbers-> 15, 30, 45, 60, 75, 90
Favourable number of ways = 6C4
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