Question
The mean of $1^3 , 2^3 , 3^3 , 4^3 , 5^3 , 6^3 , 7^3$ is
Answer: Option A
Answer:(a)Sum of the cubes of first n natural numbers = $({n(n + 1)}/2)^2$Their average = ${n(n+1)^2}/4$Required average when n = 7,= ${7(7+ 1)^2}/4 = {7 × 8×8}/4$ = 112
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Answer:(a)Sum of the cubes of first n natural numbers = $({n(n + 1)}/2)^2$Their average = ${n(n+1)^2}/4$Required average when n = 7,= ${7(7+ 1)^2}/4 = {7 × 8×8}/4$ = 112
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