Question
If $3^10 × 27^2 = 9^2 × 3^n$ then the value of n is :
Answer: Option A
Answer:(a)$3^10 × 27^2 = 9^2 × 3^n$$3^10 × (3^3)^2 = (3^2)^2 × 3^n$$3^10 × 3^6 = 3^4 × 3^n$$3^{10+6} = 3^4 × 3^n$$3^16 = 3^{4 + n}$4 + n = 16n = 16 - 4 = 12
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Answer:(a)$3^10 × 27^2 = 9^2 × 3^n$$3^10 × (3^3)^2 = (3^2)^2 × 3^n$$3^10 × 3^6 = 3^4 × 3^n$$3^{10+6} = 3^4 × 3^n$$3^16 = 3^{4 + n}$4 + n = 16n = 16 - 4 = 12
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