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Question
The value of ${(243)^{0.13} × (243)^{0.07}}/{(7)^{0.25} × (49)^{0.075} × (343)^{0.2}}$
Options:
A .  1$3/7$
B .  $3/7$
C .  2$2/7$
D .  $7/3$
Answer: Option B
Answer: (b)${(243)^{0.13} × (243)^{0.07}}/{(7)^{0.25} × (49)^{0.075} × (343)^{0.2}}$Expression= ${(243)^{0.13+0.07}/{(7)^{0.25} × (7×7)^{0.075} × (7×7×7)^{0.2}}$= ${(3^5)^{0.2}/{(7)^{0.25} × (7)^{2×0.075} × (7)^{3×0.2}}$= ${(3)^{5×0.2}/{(7)^{0.25 + 0.15 + 0.6} = 3/7$

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