The limiting molar conductivities λ∘ for NaCl,KBr and KCl are 126,&

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Question

The limiting molar conductivities

λ^{\circ}

for

N a C l, K B r

and

K C l

are

126, 152

and

150 S c m^{2} m o l^{- 1}

respectively. The

λ^{\circ}

for

N a B r

is

Options:

A . 278 S cm2mol−1

B . 176 S cm2mol−1

C . 128 S cm2mol−1

D . 302 S cm2mol−1

Answer: Option C
:
C

(126 s c m^{2}) \land_{N a C l}^{\circ} = \land_{N a +}^{\circ} + \land_{C l^{-}}^{\circ}

. . . . . . . (1)

(152 s c m^{2}) \land_{K B r}^{\circ} = \land_{K^{+}}^{\circ} + \land_{B r^{-}}^{\circ}

. . . . . . . (2)

(150 s c m^{2}) \land_{K C l}^{\circ} = \land_{K^{+}}^{\circ} + \land_{C l^{-}}^{\circ}

. . . . . . . (3)

By equation

(1) + (2) - (3)

∵ \land_{N a B r}^{\circ} = \land_{N a +}^{\circ} + \land_{B r^{-}}^{\circ} = 126 + 152 - 150 = 128 S c m^{2} m o l^{- 1}

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