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Given standard electrode potentials 
Fe+++2eFe; E=0.440 V
Fe++++3eFe; E=0.036 V
The standard electrode potential (E)  for Fe++++eFe++ is
Options:
A .  - 0.476 V
B .  - 0.404 V
C .  + 0.404 V
D .  + 0.772 V
Answer: Option D
:
D
ΔG=nEF
Fe2++2eFe .......(i)
ΔG=2×F×(0.440V)=0.880F
Fe3++3eFe ......(ii)
ΔG=3×F×(0.036)=0.108F
On substracting equation (i) from (ii)
Fe3++eFe2+
ΔG=0.108F0.880F=0.772F
E for the reaction =ΔGnF=(0.772F)1×F=+0.772V

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