E∘ for the cell is Zn |Zn2+ (aq)||Cu2+ (aq)| Cu at 25

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E^{\circ}

for the cell is

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

at

25^{\circ} C

, the equilibrium constant for the reaction

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +} (a q)

is of the order of

Options:

A . 10−37

B . 10−28

C . 10+18

D . 10+17

Answer: Option A
:
A

E_{c e l l}^{\circ} = \frac{0.059}{n} l o g K

l o g K = \frac{1.10 \times 2}{0.059} = 37.2881 \Rightarrow K = 10^{- 37}

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