Question
The coefficient of x7 in the expansion of (1−x−x2+x3)6. is?
Answer: Option D
:
D
(1−x−x2+x3)6=(1−x)6(1−x2)6=(1−6C1x+6C2x2−6C3x3+6C4x4−6C5x5+6C6x6)(1−6C1x2+6C2x4−6C3x6+⋯)
⇒ coefficient of x7 is
6C1.6C3−6C3.6C2+6C5.6C1=6×20−20×15+6×6=−144
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:
D
(1−x−x2+x3)6=(1−x)6(1−x2)6=(1−6C1x+6C2x2−6C3x3+6C4x4−6C5x5+6C6x6)(1−6C1x2+6C2x4−6C3x6+⋯)
⇒ coefficient of x7 is
6C1.6C3−6C3.6C2+6C5.6C1=6×20−20×15+6×6=−144
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