Question
In (3√2+13√3)n if the ratio of 7th term from the beginning to the 7th term from the end is 16, then n =
Answer: Option C
:
C
16=nC6(213)n−6(3−13)6nCn−6(213)6(3−13)n−6
6−1=613(n−12)
n−12=−3
n=9
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:
C
16=nC6(213)n−6(3−13)6nCn−6(213)6(3−13)n−6
6−1=613(n−12)
n−12=−3
n=9
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