6 t h term in expansion of ( 2 x 2 − 1 3 x 2 ) 10 is Options: A . &nbsp458017 B . &nbsp- 89627 C . &nbsp558017 D . &nbspNone of these

Answer: Option B : B Applying T r + 1 = n C r x n − r d for ( x + a ) n Hence T 6 = 10 C 5 ( 2 x 2 ) 5 (- 1 3 x 2 ) 5 = - ( 10 ! 5 ! 5 ! ) (32) ( 1 243 ) = - 896 27

6th term in expansion of (2x2−13x2)10 is

Question

6^{t h}

term in expansion of

(2 x^{2} - \frac{1}{3 x^{2}})^{10}

Options:

A . 458017

B . - 89627

C . 558017

D . None of these

Answer: Option B
:
B
Applying

T_{r + 1}

^{n} C_{r}

x^{n - r} d

for

(x + a)^{n}

Hence

T_{6}

^{10} C_{5}

(2 x^{2})^{5}

\frac{1}{3 x^{2}})^{5}

= -

(\frac{10!}{5! 5!})

(32)

(\frac{1}{243})

= -

\frac{896}{27}

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