Question
The number of integral terms in the expansion of (√3+8√5)256 is ?
Answer: Option B
:
B
(√3+8√5)256∴Tr+1=256Cr(√3)256−r(8√5)r=256Cr(3)256−r2(5)r8
Terms would be integeral if (256−r)2 And r8 are possitive integers.
As 0≤r≤256
r=0,8,16,24⋯256
For the above values of r, (256−r)2 is also an integer. Hence, the total number fo values of r is 33.
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:
B
(√3+8√5)256∴Tr+1=256Cr(√3)256−r(8√5)r=256Cr(3)256−r2(5)r8
Terms would be integeral if (256−r)2 And r8 are possitive integers.
As 0≤r≤256
r=0,8,16,24⋯256
For the above values of r, (256−r)2 is also an integer. Hence, the total number fo values of r is 33.
Was this answer helpful ?
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