Question
The first 3 terms in the expansion of (1+ax)n (n ≠ 0) are 1, 6x and 16x2. Then the value of a and n are respectively
Answer: Option C
:
C
nc1.ax=6x;nc2(ax)2=16x2⇒an=6;n(n−1)2a2=16⇒a=23⇒n=9
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:
C
nc1.ax=6x;nc2(ax)2=16x2⇒an=6;n(n−1)2a2=16⇒a=23⇒n=9
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