Question
Propan-1-ol can be prepared from propene by alcohol
Answer: Option C
:
C
When propene reacts with mercuric acetate followed by NaBH4, it gives secondary or tertiary alcohols, in accordance with Markownikoff’s rule. But, with diborane followed by H2O2, it gives primary alcohols which is in accordance with Anti-Markownikoff’s rule. 6CH3−CH=CH2+B2H6H2O2−−−→CH3−CH2−CH2OH
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:
C
When propene reacts with mercuric acetate followed by NaBH4, it gives secondary or tertiary alcohols, in accordance with Markownikoff’s rule. But, with diborane followed by H2O2, it gives primary alcohols which is in accordance with Anti-Markownikoff’s rule. 6CH3−CH=CH2+B2H6H2O2−−−→CH3−CH2−CH2OH
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