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Question

Pipes A and B can fill a tank in 5 and 6 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:

Options:
A .  \(1\frac{13}{17}hours\)
B .  \(2\frac{8}{11}hours\)
C .  \(3\frac{9}{17}hours\)
D .  \(4\frac{1}{2}hours\)
Answer: Option C

Net part filled in 1 hour \(\left(\frac{1}{5}+\frac{1}{6}-\frac{1}{12}\right)=\frac{17}{60}.\)


So, The tank will be full in  \(\frac{60}{17}.\)   hours i.e.,  \(3\frac{9}{17}hours\)


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