A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes r

Question

A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half?

Options:

A . 15 min

B . 20 min

C . 27.5 min

D . 30 min

Answer: Option D

Part filled by (A + B) in 1 minute = $\left(\frac{1}{60}+\frac{1}{40}\right)=\frac{1}{24}$

Suppose the tank is filled in x minutes.

Then, $\frac{x}{2}\left(\frac{1}{24}+\frac{1}{40}\right)=1$

$\frac{x}{2}\times\frac{1}{15}=1$

x=30min

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