Question
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Answer: Option C
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Suppose pipe A alone takes x hours to fill the tank.
Then, pipes B and C will take \(\frac{x}{2}and\frac{x}{4}\) hours respectively to fill the tank
So, \(\frac{1}{x}+\frac{2}{x}+\frac{4}{x}=\frac{1}{5}\)
\(\frac{7}{x}=\frac{1}{5}\)
x = 35 hrs.
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