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Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?

Options:
A .  1 hour
B .  2 hours
C .  6 hours
D .  8 hours
Answer: Option C

Let the cistern be filled by pipe A alone in x hours.


Then, pipe B will fill it in (x + 6) hours.


So, \(\frac{1}{x}+\frac{1}{(x+6)}=\frac{1}{4}\)


\(\frac{x+6+x}{x(x+6)}=\frac{1}{4}\)


x2 - 2x - 24 = 0


 (x -6)(x + 4) = 0


 x = 6.     [neglecting the negative value of x]


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