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Question


Minimum value of 5sin2θ+4cos2θ is


Options:
A .   1
B .   2
C .   3
D .   4
Answer: Option D
:
D

Let f(θ) = 5sin2θ+4cos2θ = 4+sin2θ


f(θ) 4 + 0                         (sin2θ0


∴  The minimum value of f(θ) is 4.



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