If sinA=sinB and cosA=cosB, then Options: A . &nbsp sin A − B 2 = 0 B . &nbsp sin A + B 2 = 0 C . &nbsp cos A − B 2 = 0 D . &nbsp cos (A + B) = 0

Answer: Option A : A We have sin A = sin B and cos A = cos B 2 c o s ( A + B 2 ) s i n ( A − B 2 ) = 0 , − 2 s i n ( A + B 2 ) s i n ( A − B 2 ) = 0 Hence, sin ( A − B 2 ) = 0.

If sinA=sinB and cosA=cosB, then

Question

If sinA=sinB and cosA=cosB, then

Options:

A . sin

\frac{A - B}{2}

= 0

B . sin

\frac{A + B}{2}

= 0

C . cos

\frac{A - B}{2}

= 0

D . cos (A + B) = 0

Answer: Option A
:
A

We have sin A = sin B and cos A = cos B

$2 c o s (\frac{A + B}{2}) s i n (\frac{A - B}{2}) = 0, - 2 s i n (\frac{A + B}{2}) s i n (\frac{A - B}{2}) = 0$

Hence, sin $(\frac{A - B}{2})$ = 0.

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