1 t a n 3 A − t a n A - 1 c o t 3 A − c o t A = Options: A . &nbsp tanA B . &nbsp tan2A C . &nbsp cotA D . &nbsp cot2A

Answer: Option D : D 1 t a n 3 A − t a n A - 1 c o t 3 A − c o t A = 1 t a n 3 A − t a n A + t a n A t a n 3 A t a n 3 A − t a n A = 1 t a n 2 A = cot 2A.

1tan3A−tanA - 1cot3A−cotA =

Question

$\frac{1}{t a n 3 A - t a n A}$ - $\frac{1}{c o t 3 A - c o t A}$ =

Options:

A . tanA

B . tan2A

C . cotA

D . cot2A

Answer: Option D
:
D

$\frac{1}{t a n 3 A - t a n A}$ - $\frac{1}{c o t 3 A - c o t A}$

= $\frac{1}{t a n 3 A - t a n A}$ + $\frac{t a n A t a n 3 A}{t a n 3 A - t a n A}$ = $\frac{1}{t a n 2 A}$ = cot 2A.

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