Maximum number of atoms are present in

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Question

Maximum number of atoms are present in

Options:

A . 11.2 litresof SO2at STP

B . 22.4 litres of Helium at STP

C . 2.0 g. of hydrogen

D . 11.2 litres of methane at STP

Answer: Option D
:
D
No. of atoms in

11.2 l i t .

of

S O_{2}

=

\frac{11.2}{22.4} \times N_{A} \times 3 = 1.5 N

No. of Atoms in

2 g

H_{2}

=

\frac{2}{2} \times N_{A} \times 2 = 2 N

No. of Atoms in

22.4 l i t .

of

H e

=

\frac{22.4}{22.4} \times N_{A} = N

No. of Atoms in

11.2 l i t

of

C H_{4}

=

\frac{11.2}{22.4} \times N_{A} \times 5

=

2.5 N

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